> 数学 >
已知x=(√3+√2)/(√3-√2),y=(√3-√2)/(√3+√2),则代数式x²-3xy+y²
人气:116 ℃ 时间:2019-08-22 12:09:40
解答
x=(√3+√2)/(√3-√2)=(√3+√2)²/(3-2)=(3+2√6+2)/1=5+2√6
y=(√3-√2)/(√3+√2))=(√3-√2)²/(3-2)=(3-2√6+2)/1=5-2√6
xy=(√3+√2)/(√3-√2)* (√3-√2)/(√3+√2)=1
x²-3xy+y²
=(x²+2xy+y²)-5xy
=(x+y)²-5*1
=(5+2√6+5-2√6)²-5
=10²-5
=95
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版