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1*3,2*4,3*5,...n(n+2)求数列的前n项和Sn的详细步骤,最好有,每一步,答案是n(n+1)(2n+7)/6
人气:285 ℃ 时间:2020-07-16 22:24:35
解答
原式=1×(1+2)+2×(2+2)+3×(3+2)+……+n(n+2)
=1²+2²+3²+……+n²+2×(1+2+3+……+n)
=1/6×n(n+1)(2n+1)+n(n+1)
=1/6n(n+1)(2n+7)
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