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y=1+cosx/1-cosx 求dy
人气:293 ℃ 时间:2020-08-15 04:10:41
解答
y = (1+cosx)/(1-cosx)
dy = [ (1+cosx)/(1-cosx) ] ' dx
= [ (-sinx)*(1-cosx) - (1+cosx)*sinx ] / (1-cosx)^2 dx
= - 2sinx / (1-cosx)^2 dx
懂了请采纳o(∩_∩)o
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