设原方程为ax+by=c（c≠0）,将两个解代入得 a+2b=c ① -7a-3b=c ② ①×7+②得 11b=8c→b=8/11c ①×3+②×2得 -11a=5c→a=-5/11c 所以原方程为-5/11cx+8/11cy=c,即-5/11x+8/11y=1
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