lim(x→0) (e^x-sinx-1)/(arcsinx^2)
=lim(x→0) (e^x-sinx-1)/x^2(0/0)
=lim(x→0) (e^x-cosx)/(2x)(0/0)
=lim(x→0) e^x+sinx
=12x再导一次应该为2了哇噢，居然算忘记了，晕了，那结果是1/2