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化简:m/(m-n)根号(m^3-2m^2n+mn^2)(m
人气:109 ℃ 时间:2019-12-13 16:43:18
解答
根号(m^3-2m^2n+mn^2)
=根号{m(m^2-2mn+n^2}=(n-m)根号m
m/(m-n)根号(m^3-2m^2n+mn^2)
=m/(m-n)}*(n-m)根号m
=-m^(3/2)
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