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(1×2×4+2×4×8+3×6×12+……+6×12×24)÷(1×3×9+2×6×18+3×9×27+……+6×18×54)=?
人气:210 ℃ 时间:2019-09-23 14:12:08
解答
8/27过程(1×2×4+2×4×8+3×6×12+……+6×12×24)÷(1×3×9+2×6×18+3×9×27+……+6×18×54)=(1×2×4+2^3(1×2×4)+3^3(1×2×4)+......+6^3(1×2×4)) ÷(1×3×9+2^3(1×3×9)+3^3(1×3×9)+......+6^3(1×3×9)) =(1+2^3+3^3+......6^3)(1×2×4) ÷ (1+2^3+3^3+......6^3)(1×3×9)=(1×2×4) ÷ (1×3×9)=8/27
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