求数学计算公式
第1个格子放1颗豆豆,第2个格子放2颗豆豆,第3个格子放3颗豆豆,第4个格子放4颗豆豆.以此类推,计算第10个格子的时候一共放了多少个豆豆?应该怎么计算呢?
人气:403 ℃ 时间:2020-03-19 12:40:23
解答
an为第n项的通项公式,an=a1+(n-1)d,(n为正整数)a1为首项,an为第n项的通项公式,d为公差.前n项和公式为:Sn=na1+n(n-1)d/2或Sn=n(a1+an)/2,(n为正整数)
你这个是a1=1.d=1,
第10个格子一共放了 S10=10(1+10)/2=55
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