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在△ABC中,a=4sin10°,b=2sin50°,C=70°,则S△ABC=?
人气:309 ℃ 时间:2019-11-11 13:40:45
解答
直接用正弦定理了!
S=absinC/2
=4sin10sin50sin70
=2sin50[cos(10-70)-cos(10+70)]
=2sin50[cos60-cos80]
=sin50-2sin50cos80
=sin50-[sin(50+80)+sin(50-80)]
=sin50-sin130+sin30
=sin50-sin50+sin30
=1/2
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