能帮我解一下3次方程 x^3—4^2—9x+36=0 这个式子
人气：430 ℃ 时间：2020-03-27 08:02:27
解答
X^3—4X^2—9X+36=0
X^2(X-4)-9(X-4)=0
(X^2-9)(X-4)=0
x^2-9=0或x-4=0
所以x=3或x=-3或x=4
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