不是的,前一个是x的取值范围,即4<=x<=7所以1<=x-3<=4
【1,4】指的是括号里面的取值大小.ok?
f(x-3)的定义域为[4,7]
j即4<=x<=7
1<=x-3<=4
所以f(x)定义域是1<=x<=4
则f(x^2)中1<=x^2<=4
-2<=x<=-1,1<=x<=2
所以是[-2,-1]∪[1,2]