[(b^4)/(-2ab+a^2+b^2)]*[(a^3+2b^2-2a^2-2a^2b)/(b^3)]/[(b^2-a^2)/(_数学解答

[(b^4)/(-2ab+a^2+b^2)]*[(a^3+2b^2-2a^2-2a^2b)/(b^3)]/[(b^2-a^2)/(ab+b^2)]因式分解····

人气：435 ℃　时间：2020-04-03 02:11:38

解答

[(b^4)/(-2ab+a^2+b^2)]*[(a^3+2b^2-2a^2-2a^2b)/(b^3)]/[(b^2-a^2)/(ab+b^2)]因式分解····[(b^4)/(-2ab+a^2+b^2)]*[(a^3+2b^2-2a^2-2a^2b)/(b^3)]/[(b^2-a^2)/(ab+b^2)]=[b^4/(b-a)^2]*[(a^3+2b^2-2a^2-2a^2b)/...