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[(b^4)/(-2ab+a^2+b^2)]*[(a^3+2b^2-2a^2-2a^2b)/(b^3)]/[(b^2-a^2)/(ab+b^2)]因式分解····
人气:162 ℃ 时间:2020-04-03 02:11:38
解答
[(b^4)/(-2ab+a^2+b^2)]*[(a^3+2b^2-2a^2-2a^2b)/(b^3)]/[(b^2-a^2)/(ab+b^2)]因式分解····[(b^4)/(-2ab+a^2+b^2)]*[(a^3+2b^2-2a^2-2a^2b)/(b^3)]/[(b^2-a^2)/(ab+b^2)]=[b^4/(b-a)^2]*[(a^3+2b^2-2a^2-2a^2b)/...
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