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数学
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如图,五边形ABCDE的内角都相等,且∠1=∠2,∠3=∠4,求X
人气:431 ℃ 时间:2020-02-05 16:45:01
解答
∵ABCDE是五边形 ∴此内角和为180×(5-2)=540 ∵∠E=∠C=∠EAB=∠ABC=∠CDE ∴∠E=∠C=∠EAB=∠ABC=∠CDE=540÷5=108 ∴∠1+∠2=180°-∠E=72° ∵∠1=∠2 ∴∠1=72°÷2=36°
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