由韦达定理x1*x2=1x1+x2=tanα+cotαx1=√2-√3则x2=1/x1=1/(√2-√3)=-√2-√3x1+x2=√2-√3-√2-√3=-2√3tanα+cotα=sinα/cosα+cosα/sinα=[(sinα)^2+(cosα)^2]/(sinαcosα)=1/(sinαcosα)1/(sinαcosα)...