1/(x²-6x+9)+1/(2x+6)=x/(x²-9)1/(x-3)²+1/[2(x+3)]=x/[(x+3)(x-3)]去分母,等式两边同乘以2(x+3)(x-3)²2(x+3) +(x-3)²=2x(x-3)整理,得x²-2x-15=0(x-5)(x+3)=0x=5或x=-3代入分式方程检...