| 1 |
| x+2 |
| (x−2)2 |
| x(x−1) |
| (x+1)(x−1)−3 |
| x−1 |
=
| 1 |
| x+2 |
| (x−2)2 |
| x(x−1) |
| x−1 |
| (x+2)(x−2) |
=
| 1 |
| x+2 |
| x−2 |
| x(x+2) |
=
| 2 |
| x2+2x |
由x2+2x-4=0，得x2+2x=4，
原式=
| 2 |
| 4 |
| 1 |
| 2 |
| 1 |
| x+2 |
| x2−4x+4 |
| x2−x |
| 3 |
| x−1 |
| 1 |
| x+2 |
| (x−2)2 |
| x(x−1) |
| (x+1)(x−1)−3 |
| x−1 |
| 1 |
| x+2 |
| (x−2)2 |
| x(x−1) |
| x−1 |
| (x+2)(x−2) |
| 1 |
| x+2 |
| x−2 |
| x(x+2) |
| 2 |
| x2+2x |
| 2 |
| 4 |
| 1 |
| 2 |