二元一次方程(x+y)/2+(x-y)/3=6,4(x+y)-5(x-y)=2怎么算_数学解答

二元一次方程(x+y)/2+(x-y)/3=6,4(x+y)-5(x-y)=2怎么算

人气：317 ℃　时间：2020-02-05 05:43:51

解答

(x+y)/2+(x-y)/3=6
3(x+y)+2(x-y)=36
5x+y=36
4(x+y)-5(x-y)=2
-x+9y=2
5x-45y=-10
5x+y=36
y=1
x=7