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二元一次方程(x+y)/2+(x-y)/3=6,4(x+y)-5(x-y)=2怎么算
人气:195 ℃ 时间:2020-02-05 05:43:51
解答
(x+y)/2+(x-y)/3=6
3(x+y)+2(x-y)=36
5x+y=36
4(x+y)-5(x-y)=2
-x+9y=2
5x-45y=-10
5x+y=36
y=1
x=7
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