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数学
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化简:sin(-4π/3)cos(-23π/6)tan25π/4
人气:323 ℃ 时间:2020-06-07 07:36:27
解答
sin(-4π/3)cos(-23π/6)tan25π/4
=sin(2π-4π/3)cos(4π-23π/6)tan(25π/4-6π)
=sin(2π/3)cos(π/6)tan(π/4)
=√3/2*√3/2*1
=3/4
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