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在△ABC中,(a²+b²-c²)²-(ab)²=0,则C=
人气:433 ℃ 时间:2020-03-26 20:13:58
解答
(a²+b²-c²)²-(ab)²=0
[(a²+b²-c²)+(ab)][(a²+b²-c²)-(ab)]=0
(a²+b²-c²)+(ab)=0或(a²+b²-c²)-(ab)=0
cosC=(a²+b²-c²)/2ab=-1/2 或cosC=(a²+b²-c²)/(2ab)=1/2
C=60°或C=120°
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