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解方程 5(10x+30)-2(4x-10)=-250 (3a²-5a+4)—4(-2a²-3a+3)化简
人气:119 ℃ 时间:2020-07-26 06:13:04
解答
5(10x+30)-2(4x-10)=-25050x+150-8x+20=-25042x=-250-150-20=-420x=-420÷42=-10(3a²-5a+4)—4(-2a²-3a+3)=3a²-5a+4+8a²+12a-12=11a²+7a-8
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