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数学
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解方程组:
x+2y+3z=6
2x+3y+z=6
3x+y+2z=6
.
人气:306 ℃ 时间:2019-12-18 09:11:48
解答
x+2y+3z=6①2x+3y+z=6②3x+y+2z=6③,①+②+③得6x+6y+6z=18,所以x+y+z=3④,②-①得x+y-2z=0⑤,④-⑤得3z=3,解得z=1,③-①得2x-y-z=0⑥,④+⑥得3x=3,解得x=1,把x=1,z=1代入④得1+y+1=3,解得y=1,所以原...
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