√(5X+4)=√(2X-1)+√(3X+1)
两边平方得：
5X+4=2X-1-2√［(2X-4)(3X+1)］+3X+1
2=√［(2X-1)(3X+1)］
6X^2-x-1=4
6x^2-x-5=0,
(6x+5)(x-1)=0
x=-5/6,x=1,
经检验X=5/6是增根,
∴原方程的X=1.