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数学
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几道简单的题、帮个忙呗、
(a^2+1)-4a^2 12/(m^2-9)-2/m-3
若x/2=y/3=z/5 且3x+2y-z=14,求x,y,z
人气:465 ℃ 时间:2020-04-09 07:21:37
解答
①(a^2+1)-4a^2 =1-3a^2
② 12/(m^2-9)-2/m-3
=12/(m+3)(m-3)-2/m-3
=12-2m-6/(m+3)(m-3)
=-2/(m+3)
③这是一种题型
解题模式就是令x/2=y/3=z/5=k
得x=2k
y=3k
z=5k
代入第二个式子得k=2
x=4
y=6
z=10
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