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-2(x-y)^2n-4(y-x)^2n+1(n的值为正整数) a(x-y)^n-3b(y-x)^n+1+2c(y-x)^n+2(n的值为正整数)
人气:361 ℃ 时间:2020-04-03 12:10:04
解答
2n+1是奇数所以原式=-2(x-y)^2n+4(x-y)^2x+1=2(x-y)^2n[2(x-y)-1]=2(x-y)^2n(2x-2y-1)n奇数,原式=-a(y-x)^n-3b(y-x)^n+1+2c(y-x)^n+2=-(y-x)^n(a+3by-3bx+2cy²-4cxy+2cy²)n偶数,原式=a(y-x)^n-3b(y-x...
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