(x的平方-9)分之(2x-6)+(x+3)(x-2)分之(x的平方+2x+1)/(x-2)分之(x+1)
=2(x-3)/(x+3)(x-3) + (x+1)²/(x+3)(x-2) × (x-2)/(x+1)
=2/(x+3) + (x+1)/(x+3)
=(2+x+1)/(x+3)
=(x+3)/(x+3)
=1