(X-3)/(X+2)+m/(X²-4)=X/(X-2)
(X-2)²+m=X(X+2)去分母
6X-4-m=0化简
当原方程有增根
X=2或-2
代入,得m=8或-16是(x-2/x+2)(X-2)/(X+2)+m/(X²-4)=X/(X-2)(X-2)²+m=X(X+2)4X-4m=0化简当原方程有增根X=2代入，得m=24X-4m=0是什么(X-2)²+m=X(X+2)化简(X)²-4x+4+m=(X)²+2x 4 X-4-m=0