4x的平方=(x-1)的平方解方程怎么做
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人气：304 ℃ 时间：2020-05-07 18:26:11
解答
4x^2=(x-1)^2 4x^2-(x-1)^2=0 (2x+x-1)(2x-x+1)=0 (3x-1)(x+1)=0 x1=1/3 x2=-1
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