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1/x-1/y=2 求(2x+3xy-2y)/(x-xy-y)的值
1/x-1/y=2 求(2x+3xy-2y)/(x-xy-y)的值
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人气:403 ℃ 时间:2019-09-18 05:13:13
解答
1/x-1/y=2
等式两边同时乘以xy
y-x=2xy
x-y=-2xy
=[2(x-y)+3xy]/[(x-y)-xy]
=(-4xy+3xy)/(-2xy-xy)
=(-xy)/(-3xy)
=1/3
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