(x/x+y +2y/x+y)乘以xy/ x+2y除以(1/x+1/y)(2)(3x^2/4y)^2乘以2y/3x+ x^2/2y^2除以2y^2/x
人气:435 ℃ 时间:2019-08-18 00:25:58
解答
(x/x+y +2y/x+y)乘以xy/ x+2y除以(1/x+1/y)=(x+2y)/(x+y)*xy/(x+2y)/[(x+y)/(xy)]=xy/(x+y)*xy/(x+y)=(xy)^2/(x+y)^2(3x^2/4y)^2乘以2y/3x+ x^2/2y^2除以2y^2/x=9x^4/16y^2*2y/3x+x^2/2y^2*x/2y^2=3x^3/8y+x^3/4y^4...
推荐
- 已知x+y=5,xy=2,求5x+4y-3x-2y+xy的值
- 已知3x2+xy-2y2=0,求(x+y/x-y+4xy/y2-x2)÷x2+2xy-3y2x2-9y2的值.
- 已知 x+y=3,xy=-2,求(3x-2y+8xy)-(x-4y-5xy)的值
- 8x^2y^4除以(-3x/4y^2)除以(-xy^2/2)
- [x(x^2y^2-xy)-y(x^2-x^3y)]除以3x^2y
- 照样子,在括号里填上合适的词语.
- 临近毕业李红和王芳想折一些纸鹤送给老师留作纪念,李红单独折要4小时,王芳单独折要5
- 5,6,8,7,2,4,6,10,3,9,6,14+的中位数如何求?
猜你喜欢