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请你求出下列三张卡片上的多项式的和,并求x=2013,y=-1,该多项式和的值.
2(x²+xy) -(xy+3x²y) x²y
人气:348 ℃ 时间:2020-06-18 13:49:30
解答
2(x²+xy)-(xy+3x²y)+x²y
=2x²+2xy-xy-3x²y+x²y
=2x²+xy-2x²y
=x(2x+y-2xy)
x=2013,y=-1
2(x²+xy)-(xy+3x²y)+x²y
=x(2x+y-2xy)
=2013*(2*2013+1-2*2013*1)
=2013*1
=2013
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