被积函数 = 1/[2u^2·(1-u^2)] = (1/2)·[(1/u^2) + [1/(1 - u^2)]]= (1/2)[u^(-2) + (1/2)[1/(1-u)] + (1/2)[1/(1+u)]] = (1/2)u^(-2) + (1/4)[1/(1-u)] + (1/4)[1/(1+u)]∴原积分 =...