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(2x^3y^3-2x^3y+1/8^4+y)/(-1/2x^3y)
怎么算!
人气:100 ℃ 时间:2020-09-19 19:37:12
解答
(2x^3y^3-2x^3y+1/8^4+y)/(-1/2x^3y)=-2(2x^3y^3-2x^3y+1/8^4+y)/(x^3y)=-2(2y^2-2)+2(1/8^4+y)/(x^3y)=-4y^2-4+2/8^4(x^3y)+2y/(x^3y)=-4y^2-4+2/2^12(x^3y)+2/x^3=-4y^2-4+1/2^11x^3y+2/x^3
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