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4x²-12xy+9y²-2x+3y-6 用十字相乘法
人气:148 ℃ 时间:2019-09-09 18:33:39
解答
4x²-12xy+9y²-2x+3y-6
=(2x-3y)²-(2x-3y)-6
=(2x-3y+2)(2x-3y-3)
其中把2x-3y看成整体
十字相乘法就是:
2x-3y +2
2x-3y -3
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4x2+9y2=(2x+3y)2+_=(2x-3y)2+_.
((4x^2-12xy+9y^2)-(4x^2-9y^2))/(2x-3y)
4x²y-12xy²+9y³
(2x-3y)(2x+3y)(9y²+4x²)求解答要过程
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