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数学
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已知tan(派-阿拉法)=2,求2/sin平方阿拉法-sin阿拉法cos阿拉法-cos平方阿拉法的值
人气:492 ℃ 时间:2020-09-22 19:33:17
解答
由于tan(π-α)=2,tanα=-2
cos²α=4/5
式子分子分母同除cos²α得
(2/cos²α)/(tan²α-tanα-1)=(5/2)/(4+2-1)=5/14亲,再帮我一小下啦。。。化简sin(-派+阿拉法)sin(3派-阿拉法)cos(-阿拉法-派)/sin(2派-阿拉法)cos(3派+阿拉法)式子=[-sin(π-α)sin(π-α)cos(π+α)]/[sin(-α)cos(π+α)] =[-sinαsinα(-cosα)]/[-sinα(-cosα)] =sinα
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