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化简:[sin(540°-a)tan(a-270°)cos(a-270°)]/[cos(a-180°)tan(810°+a)sin(-a-180°)]
人气:337 ℃ 时间:2020-06-10 14:54:35
解答
sin(540°-a)=sina
tan(a-270°)=-cosa/sina
sin(540°-a)tan(a-270°)cos(a-270°)=-cosa
cos(a-180°)=-cosa
tan(810°+a)=tana=sina/cosa
sin(-a-180°)=sina
cos(a-180°)tan(810°+a)sin(-a-180°)=-sin^2a
:[sin(540°-a)tan(a-270°)cos(a-270°)]/[cos(a-180°)tan(810°+a)sin(-a-180°)]
=-cosa/sin^2a
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