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数学题化简再求值
(1/x-y+1/x+y)÷x^2 y^2/x^2-y^2,其中x=3,y=-√2
人气:378 ℃ 时间:2020-02-04 09:22:10
解答
(1/x-y+1/x+y)÷x^2 y^2/x^2-y^2=(2x)/(x^2-y^2)÷(x^2 y^2)/(x^2-y^2)=(2x)/(x^2-y^2)÷(x^2-y^2)/(x^2 y^2)=2/(xy^2)当x=3,y=-√2 时2/(xy^2)=2/(3*2)=1/3江苏吴云超祝你学习进步
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