1.已知|x+1|=4,（y+2）²=4,求x+y的值
|x+1|=4打开不等式
x+1=4 or -4
x= 3 or -5
(y+2）²=4
开根号
y+2= 2 or -2
y=0 or -4
所以 x+y= 3 or -5 or -1 or -9
2.-1²-〔1又3/7+(-12)÷6〕²×(-3/4)³
=-1-(10/7-2)^2*(-27/64)
= -1-(-4/7)^2*（-27/64）
= -1+16/49*27/64
= -1+27/196
=-159/196