{（2X）除以（2X-5）-（2）除以（2X+5）}=1
(2x)/(2x-5)-2/(2x+5)=1
(2x)(2x+5)/[(2x-5)(2x+5)]-2(2x-5)/[(2x-5)(2x+5)]=1
[(4x^2+10x)-(4x-10)] / [(2x-5)(2x+5)] =1
4x^2+6x+10=(2x-5)(2x+5)
4x^2+6x+10=4x^2-25
6x=-25-10
6x=-35
x=-35/6