已知X^2-5X-1999=0则分式{（X-2)^3-(X-1)^2+1}/X-2_数学解答

已知X^2-5X-1999=0则分式{（X-2)^3-(X-1)^2+1}/X-2

人气：390 ℃　时间：2020-06-05 17:35:49

解答

先化简分式,再将X^2-5X-1999=0代入.
{(X-2)^3-(X-1)^2+1}/(X-2)={(X-2)^3-(X^2-2X+1)+1}/(X-2)= {(X-2)^3-(X^2-2X)}/(X-2)={(X-2)^3-X(X-2)}/(X-2)=(X-2){(X-2)^2-X}/(X-2)= (X-2)^2-X=X^2-5X+4= (X^2-5X-1999)+2003=2003