2a=3b2a=3b求4a²+12ab+9a²/2a²+5ab+3b²_数学解答

2a=3b2a=3b求4a²+12ab+9a²/2a²+5ab+3b²

人气：422 ℃　时间：2020-04-08 09:28:39

解答

应该是：（4a²+12ab+9b²）/（2a²+5ab+3b²）
=(2a+3b)^2/(2a+3b)(a+b)
=(2a+3b)/(a+b)
代入：2a=3b
=(3b+3b)/(b+3b/2)
=6b/(5b/2)
=6/(5/2)
=6*2/5
=12/5