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求函数y=log2(x^2+1/4)-log2x(2为底)值域
人气:149 ℃ 时间:2019-10-11 01:49:09
解答
log2(x^2+1/4)-log2x=log2[(x^2+1/4)/x]
f(x)=[(x^2+1/4)/x]
=x+1(4x) x>0
f(x)'=1-1/[4(x^2)]
1/(4x^2)>1时,f(x)'
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