1/(2^x -1)>1/(1- 2^(x-1))令2^(x-1)=t,则2^x=2*2^(x-1)=2t∴1/(2t-1)>1/(1-t)1/(2t-1)+1/(t-1)>0(3t-2)/[(2t-1)(t-1)]＞0∴t＞1或t∈﹙1/2,2/3﹚即2^(x-1）＞1或1/2＜2^(x-1）＜2/3x-1＞0 or -1＜x-1＜log﹙2﹚﹙2...