函数f(x)=x²-mx+2x-1,x∈[2,3]是单调递增函数,求m的取值范围
人气：363 ℃ 时间：2020-04-23 04:28:56
解答
答：
f(x)=x^2-mx+2x-1
=x^2-(m-2)x-1
在2
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