已知(3x+1)的平方+ly-1l=0,3x+1=0;x=-1/3;y-1=0;y=1;求4(x-2分之1y)-[2y+3(x+y)+3xy]的值=4x-2y-(2y+3x+3y+3xy)=x-7y-3xy=-1/3-7×1-3×1/3×1=-1/3-7+1=-19/3;很高兴为您解答,skyhunter002为您答疑解惑如果本题有什...