> 数学 >
ln (1+x^2)x dx,积分等于多少啊?
人气:278 ℃ 时间:2020-01-28 18:56:55
解答
原式=∫ln(x+x^3)dx
=xln(x+x^3)-∫xdln(x+x^3)
=xln(x+x^3)-∫x*1/(x+x^3)*(1+3x^2)dx
=xln(x+x^3)-∫(1+3x^2)/(1+x^2)dx
=xln(x+x^3)-∫[3-2/(1+x^2)]dx
=xln(x+x^3)-3x+2arctanx+C
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版