已知弧长为C=6.8米,弦长为L=6米,求拱形的高度H?
弧半径为R.
Rn+1=(1+(L-2*Rn*SIN(C/(2*Rn)))/(L-C*COS(C/(2*Rn))))*Rn
R0=4
R1=3.973
R2=3.973
R=3.973米
H=R-(R^2-(L/2)^2)^0.5
=3.973-(3.973^2-(6/2)^2)^0.5
=1.368米