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已知A为3阶方阵,且 |A |=1/2.则 |(2A)* |=
人气:428 ℃ 时间:2020-06-16 15:30:32
解答
知识点:1.(kA)* = k^(n-1)A*2.|kA| = k^n|A|3.|A*| = |A|^(n-1)|(2A)*| = |2^(n-1)A*| = 2^[n(n-1)] |A*| = 2^[n(n-1)] |A|^(n-1)= 2^[n(n-1)] (1/2)^(n-1)= 2^[(n-1)^2]
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