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函数y=2x²-2x+3/x²-x+1的值域是
人气:474 ℃ 时间:2020-02-20 21:11:15
解答
函数y=2x²-2x+3/x²-x+1的定义域为R
y=2x²-2x+3/x²-x+1=2x²-2x+2+1/x²-x+1=2(x²-x+1)+1/x²-x+1=2+1/x²-x+1
x²-x+1=(x-1/2)²+3/4∴x²-x+1≥3/4∴0<1/x²-x+1≤4/3∴2<2+1/x²-x+1≤10/3
∴值域为(2,10/3].
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