f(x)=sin(pi*x/4-pi/6)-2cos^2(pi*x/8)+1 =(sqrt(3)/2)*sin(pi*x/4)-1/2*cos(pi*x/4)-cos(pi*x/4) =(sqrt(3)/2)*sin(pi*x/4)-3/2*cos(pi*x/4) =sqrt(3)*sin(pi*x/4+a)所以它的最小正周期为2pi*4/pi=8 其...