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化简:cos(a+π)sin²(a+3π)/tan(a+π)cos³(-a-π)
人气:384 ℃ 时间:2020-05-08 02:10:10
解答
cos(a+π)=-cosasin(a+3π)=sin(a+π)=-sina所以sin²(a+3π)=sin²atan(a+π)=tana=sina/cosacos(-a-π)=cos(a+π)=-cosacos³(-a-π)=-cos³a-cosa×sin²a/sina×(-cos²a)=tana
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